How to remove all empty nodes from an XmlDocument in c#

I've used xsl before for stripping out unwanted empty nodes from passed xml - but now needed it for some c# code. So I created the following chunk of code and it works a treat.

This is the xslt which does all the hard work...

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output omit-xml-declaration="no" indent="no"/>
    <xsl:strip-space elements="*" />
    <xsl:template match="*[not(node()) and not(./@*)]"/>
    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

And some code...

    //Xsl to strip stylesheet
    string strippingStylesheet = "<?xml version=\"1.0\" encoding=\"UTF-8\" ?><xsl:stylesheet version=\"1.0\" xmlns:xsl=\"http://www.w3.org/1999/XSL/Transform\"><xsl:output omit-xml-declaration=\"no\" indent=\"no\"/><xsl:strip-space elements=\"*\" /><xsl:template match=\"*[not(node()) and not(./@*)]\"/><xsl:template match=\"@* | node()\"><xsl:copy><xsl:apply-templates select=\"@* | node()\"/></xsl:copy></xsl:template></xsl:stylesheet>";
 
    //Set up empty node stripper
    XmlDocument stripper = new XmlDocument();
    stripper.LoadXml(strippingStylesheet);

    //Compile here
    StringWriter output = new StringWriter();
    XslCompiledTransform emptyNodeRemover = new XslCompiledTransform();
    emptyNodeRemover.Load(stripper);
 
    //Port output to string 
    StringWriter output = new StringWriter();
    emptyNodeRemover.Transform(new XmlNodeReader(source), null, output);
    output.Flush();

    //Reload source with emptied nodes
    source.LoadXml(output.ToString());
    output.Close();
    output.Dispose();